The ideal gas law incorporates the laws of Boyle and Charles.¹ Boyle’s law states that, at a constant temperature, the product of pressure and volume (P × V) is equal to a constant. Consequently, P is proportional to 1/V (P ∝ 1/V) at constant T. However, gases do not obey Boyle’s law at temperatures approaching their point of liquefaction (i.e., the point at which the gas becomes a liquid).

Boyle’s law concerns perfect gases and is not obeyed by real gases over a wide range of pressures (see Section II for a discussion of nonideal gases). However, at infinitely low pressures, all gases obey Boyle’s law. Boyle’s law does not apply to anesthetic gases and many other gases because of the van der Waals attraction between molecules (i.e., they are nonideal gases).

Charles’ law states that, at a constant pressure, volume is proportional to temperature (i.e., V ∝ T at constant P). Gay-Lussac’s law states that, at a constant volume, pressure is proportional to temperature (i.e., P ∝ T at constant V).¹ Often, these two laws are shortened for convenience to Charles’ law. When a gas obeys both Charles’ law and Boyle’s law, it is said to be an ideal gas and obeys the ideal gas law.

In clinical situations, gases are typically mixtures of several “pure” gases. Quantifiable properties of mixtures may be determined using Dalton’s law of partial pressures. Dalton’s law states that the pressure exerted by a mixture of gases is the sum of the pressures exerted by the individual pure gases ^1,²:

(2)

where P_A, P_B, and P_C are the partial pressures of pure ideal gases.

C Diffusion of Gases

Clinically, diffusion of gases through a membrane is most applicable to gas flow across lung and placental membranes. The most commonly used relation to govern diffusion is Fick’s first law of diffusion, which states that the rate of diffusion of a gas across a barrier is proportional to the concentration gradient for the gas. Fick’s law may be expressed mathematically as follows ⁶:

(4)

where

Flux = the number of molecules crossing the membrane each second (molecules/cm²/s)

ΔC = the concentration gradient (molecules/cm³)

ΔX = the diffusion distance (cm)

D = the diffusion coefficient (cm²/s)

In general, the value of D is inversely proportional to the gas’s molecular weight as well as intrinsic properties of the membrane.

Because gases partially dissolve when they come into contact with a liquid, Henry’s law becomes important in some instances. It states that the mass of a gas dissolved in a given amount of liquid is proportional to the pressure of the gas at constant temperature. As a result, the gas concentration (in solvent) is equal to a constant × P (at constant T).¹

D Pressure, Flow, and Resistance

The laws of fluid mechanics dictate an intricate relationship among pressure, flow, and resistance. Pressure is defined as force per unit area. It is usually measured clinically in mm Hg or cm H₂O, but it is most commonly measured scientifically in pascals (Pa), or newtons of force per square meter (1 Pa = 1 N/m²).

Flow (i.e., the rate of flow) is equal to the change in pressure (pressure drop or pressure difference) divided by the resistance experienced by the fluid. For example, if the flow is 100 mL/s at a pressure difference of 100 mm Hg, the resistance is 100 mm Hg/100 mL/s, or 1 mm Hg/mL/s. In laminar flow systems only, the resistance is constant, independent of the flow rate.^7,⁸

An important formula that quantifies the relationship of pressure, flow, and resistance in laminar flow systems is given by the Hagen-Poiseuille equation. Poiseuille’s law states that the fluid flow rate through a horizontal straight tube of uniform bore is proportional to the pressure gradient (ΔP), and the fourth power of the radius (π) and is related inversely to the viscosity of the gas (µ, in g/cm·s) and the length of the tube (L, in cm). This law, which is valid for laminar flow only, may be stated as follows ^7,⁸:

(5)

See the discussion of laminar flow in Section II for further details.

When the flow rate exceeds a critical velocity (the flow velocity below which flow is laminar), the flow loses its laminar parabolic velocity profile, becomes disorderly, and is termed turbulent (Fig. 4-1). If turbulent flow exists, the relationship between pressure drop and flow is no longer governed by the Hagen-Poiseuille equation. Instead, the pressure gradient required (or the resistance encountered) during turbulent flow varies as the square of the flow rate. See the discussion of turbulent flow in Section II.

Figure 4-1 Laminar and turbulent flow. Top, Laminar flow in a long smooth pipe is characterized by smooth and steady flow with little or no fluctuations. The flow profile is parabolic in nature, with fluid traveling most quickly at the center of the tube and stationary at the edges. Bottom, Turbulent flow is characterized by fluctuating and agitated flow. Its flow profile is essentially flat, with all fluid traveling at the same velocity except at tube edges. V, Velocity.

Viscosity, µ, characterizes the resistance within a fluid to the flow of one layer of molecules over another (shear characteristics).⁷ Blood viscosity is influenced primarily by hematocrit, so that at low hematocrit blood flow is easier—that is, blood is more dilute. The critical velocity at which turbulent flow begins depends on the ratio of viscosity (µ) to density (ρ), which is defined as the kinematic viscosity (υ)—that is, υ = µ/ρ. (This is illustrated with an example in the section on turbulent flow).⁷^–⁹ The unit for viscosity is g/cm·s (poise). The typical unit for kinematic viscosity is cm²/s.

The viscosity of water is 0.01 poise at 25° C and 0.007 poise at 37° C. The viscosity of air is 183 micropoise at 18° C. Its density (dry) is 1.213 g/L.¹⁰

Density is defined as mass per unit volume (g/cm³ or g/mL). The density of water is 1 g/mL. The general relation for the density of a gas is given by the following equation:

(6)

where D₀ is a known density of the gas at temperature T₀ and pressure P₀, and D is the density of the gas at temperature T and pressure P. For dry air at 18° C and 760 mm Hg (atmospheric pressure), D = 1.213 g/L.⁴

The fall in pressure at points of flow constriction (where the flow velocity is higher) is known as the Bernoulli effect (Fig. 4-2).^7,⁸ This phenomenon is used in apparatus employing the Venturi principle, such as gas nebulizers, Venturi flowmeters, and some oxygen face masks. The lower pressure related to the Bernoulli effect sucks in (entrains) air to mix with oxygen.

Figure 4-2 Bernoulli effect. A, Diagram shows fluid flow through a tube with varying diameters. At the point of flow constriction, fluid pressure is less than at the distal end of the tube, as indicated by the height of the manometer fluid column. This effect is described by the Bernoulli equation. In the case of a horizontal pipe, the distance between the centerline of the pipe and an arbitrary datum at two different points will be the same (Z). B, Venturi tube. The lower pressure caused by the Bernoulli effect entrains air to mix with oxygen. P, Pressure; V, velocity.

One final consideration that is important in the study of the airway is Laplace’s law for a sphere (Fig. 4-3). It states that, for a sphere with one air-liquid interface (e.g., an alveolus), the relation between the transmural pressure difference, surface tension, and sphere radius is described by the following equation¹¹:

Figure 4-3 Laplace’s law for a sphere. A, Laplace’s law dictates that for two alveoli of unequal size but equal surface tension, the smaller alveolus experiences a larger intra-alveolar pressure than the larger alveolus. This causes air to pass into the larger alveolus and causes the smaller alveolus to collapse. B, Collapse of the smaller alveolus is prevented through the action of pulmonary surfactant. Surfactant serves to decrease alveolar surface tension in the smaller alveolus, which results in equal pressure in both alveoli. P, Transmural pressure difference; r, sphere radius.

(7)

where

P = transmural pressure difference (dynes/cm²; 1 dyne/cm² = 0.1 Pa = 0.000751 torr)

T = surface tension (dynes/cm)

R = sphere radius (cm)

The key point in Laplace’s law is that the smaller the sphere radius, the higher the transmural pressure. However, real (in vivo) alveoli do not obey Laplace’s law because of the action of pulmonary surfactant, which decreases the surface tension disproportionately compared with what is predicted on the basis of physical principles. When pulmonary surfactant is missing from the lungs, the lungs take on the behavior described by Laplace’s law.

E Example: Analysis of Transtracheal Jet Ventilation

Transtracheal jet ventilation (TTJV) has been used to oxygenate and ventilate patients who would otherwise perish because of a lost airway.⁶ It is a temporizing measure that is used only until an airway can be secured. It is usually employed using equipment commonly available in the operating or emergency room and often using the 50-psi wall oxygen source.^6,¹²^–¹⁴

1 Analysis

The gas flow through a catheter depends on both the resistance of the catheter-connection hose assembly and the driving pressure applied to it. If the resistance of the assembly is R, the flow (F) from the catheter is F = P_d/R, where P_d is the pressure difference between the ends of the catheter-connection assembly. R itself certainly depends on F when the flow becomes turbulent, but the flow relationship still holds. However, P_d is very close to the driving pressure (P) applied to the ventilation catheter, because the lung offers little relative back pressure. (At back pressures greater than 100 cm H₂O, the lung is likely to burst, and P is often chosen to be 50 psi, or about 3500 cm H₂O.) Therefore, the flow relationship may be simplified to F = P/R.

Next, TTJV is applied through a sequence of “jet pulses,” each resulting in a given tidal volume (e.g., 500 mL). Ignoring entrained air effects, the delivered tidal volume is equal to catheter flow × pulse duration. For a catheter flow of 30 L/min, a jet pulse lasting 1 second results in a tidal volume of 30 L/min × min = 0.5 L.

In a TTJV setup consisting of a 14-G angiographic catheter connected to a regulated oxygen source by a 4.5-foot polyvinyl chloride (PVC) tube of -inch inner diameter (ID), for oxygen flows between 10 and 60 L/min, the resistance was found to be relatively constant between 0.6 and 0.8 psi/L/min.¹⁵

Many systems for TTJV choose 50 psi for convenience (50 psi being the oxygen wall outlet pressure), although a regulator is very often used to permit lower pressures. However, 50 psi may not be an optimal pressure choice for TTJV. Using the preceding data, the pressure required for TTJV for a tidal volume of 500 mL can be calculated. Assuming that the setup resistance is 0.7 psi/L/min and the desired flow rate is 30 L/min, the driving pressure should be 0.7 × 30 = 21 psi.

II Gas Flow

A Laminar Flow

In laminar flow, fluid particles flow along smooth paths in layers, or laminas, with one layer gliding smoothly over an adjacent layer.⁷ Any tendencies toward instability and turbulence are damped out by viscous shear forces that resist the relative motion of adjacent fluid layers. Under laminar flow conditions through a tube, the flow velocity is greatest at the center of the tube flow and zero at the inner edge of the tube (Fig. 4-4; see also Fig. 4-1). The flow profile has a parabolic shape. Under these conditions in a horizontal tube, the relation between flow, tube, and gas characteristics is given by the Hagen-Poiseuille equation (Equation 5), restated as follows⁷^–⁹:

Figure 4-4 Laminar flow. Laminar gas flow through long straight tube of uniform bore has a velocity profile that is parabolic in shape, with the gas traveling most quickly at center of tube. Conceptually, it is helpful to view laminar gas flow as a series of concentric cylinders of gas, with the central cylinder moving most rapidly.

(From Nunn JF: Nunn’s applied respiratory physiology, ed 4, Stoneham, MA, 1993, Butterworth-Heinemann.)

ΔP = pressure gradient (pascals)

r = tube radius (cm)

L = tube length (cm)

µ = gas viscosity (g/cm·s)

Typical units are shown in parentheses. The dot indicates rate of change: V represents volume, and represents the rate of change of volume, or flow rate. Another way of looking at this concept is that, under conditions of laminar flow through a tube of known radius, the pressure difference across the tube is given by the following proportionality (which is also essentially the same as Equation 5):

(9)

The pressure gradient through the airway increases proportionately with flow, viscosity, and tube length but increases exponentially as the tube radius decreases.

The conditions under which flow through a tube is predominantly laminar can be estimated from critical flow rates. The critical flow is the flow rate below which flow is predominantly laminar in a given airflow situation.

1 Laminar Flow Example

Assume a tube of uniform bore that is 1 cm in diameter and 3 m in length. A pressure difference of 5 cm H₂O exists between the ends of the tube, and air is the fluid flowing through the tube. Assuming laminar flow, what flow rate should be expected?

Answer

The relevant variables are expressed in the centimeter-gram-second (CGS) system of units:

r = 0.5 cm

L = 3000 cm

µ = 183 micropoise = 183 × 10⁻⁶ poise = 183 × 10⁻⁶ g/(cm·s)

ΔP = 0.5 cm H₂O = 490 dynes/cm²

Using the Hagen-Poiseuille equation, the laminar flow is determined as follows:

(10)

B Turbulent Flow

Flow in tubes below the critical flow rate remains mostly laminar. However, at flows greater than the critical flow rate, the flow becomes increasingly turbulent. Under turbulent flow conditions, the parabolic flow pattern is lost, and the resistance to flow increases with flow itself. Turbulence may also be created where sharp angles, changes in diameter, and branches are encountered (Fig. 4-5). The flow-pressure drop relationship is given approximately by the following equation^7,⁸:

Figure 4-5 Turbulent flow. Four circumstances likely to produce turbulent flow.

(From Nunn JF: Nunn’s applied respiratory physiology, ed 4, Stoneham, MA, 1993, Butterworth-Heinemann.)

(11)

where

V = mean fluid velocity (cm/s)

ΔP = pressure (pascals)

1 Reynolds Number Calculation Example

The Reynolds number (Re) represents the ratio of inertial forces to viscous forces.^7,^8,¹⁶ It is useful because it characterizes the flow through a long, straight tube of uniform bore. It is a dimensionless number having the following form:

µ = viscosity (poise or g/cm·s)

r = radius (cm)

υ = kinematic viscosity (cm²/s) = µ/ρ

D = diameter (cm)

V = mean fluid velocity (cm/s)

Typical units are shown in brackets. For tubes that are long compared with their diameter (i.e., length ÷ diameter > 0.06 × Re),⁸ the flow is laminar when Re is less than 2000. For shorter tubes, flow is turbulent at Re values as low as 280.

When a tube’s radius exceeds its length, it is an orifice; flow through an orifice is always turbulent. Under these conditions, the flow is influenced by the density rather than the viscosity of the fluid.¹⁷ This characteristic explains why heliox (e.g., the mixture of 70% He and 30% O₂) flows better in a narrow edematous glottis: as the following data suggest, helium has a very low density and thus presents less resistance to flow through an orifice.

	Viscosity at 20° C	Density at 20° C
Helium	194.1 micropoise	0.179 g/L
Oxygen	210.8 micropoise	1.429 g/L

How can one predict whether a given gas flow through an endotracheal tube (ETT) is laminar or turbulent? One approach is first to identify the physical conditions. For example, consider the case of an ETT with a 6-mm ID and a length of 27 cm through which 1 L/min of air is passing. In this setting,

L = 27 cm

r = 0.3 cm (size 6 mm ETT)

flow () = 60 L/min = 1000 mL/s

viscosity (µ) = 183 micropoise = 183 × 10⁻⁶ g/cm·s (air at 18° C)

density (ρ) = 1.21 g/L = 0.001213 g/mL (dry air at 18° C)

With this information, one can calculate the Reynolds number:

(13)

Because this number greatly exceeds 2000, flow is probably quite turbulent.

C Critical Velocity

The critical velocity is the point at which the transition from laminar to turbulent flow begins. This point is reached when Re becomes the critical Reynolds number, Re_crit. Critical velocity, the flow velocity below which flow is laminar, is calculated by the following equation ⁸:

(14)

where Re_crit = 2000 for circular tubes.

As can be seen from this equation, the critical velocity is proportional to the viscosity of the gas and is related inversely to the density of the gas and the radius of the tube. (Viscosity has the dimensions of pascal-second (Pa × s), (equivalent to N × s/m², or kg/[m × s].)

The critical velocity at which turbulent flow begins depends on the ratio of viscosity to density, that is, µ/ρ. This ratio is known as the kinematic viscosity, υ, and has typical units of centimeters squared per second (cm²/s). The actual measurement of viscosity of a fluid is carried out with the use of a viscometer, which consists of two rotary cylinders with the test fluid flowing between.

1 Critical Velocity Calculation Example

Using the same data as in the previous Reynolds number calculation, one can calculate the critical velocity at which laminar flow starts to become turbulent:

(15)

D Flow Through an Orifice

Flow through an orifice (defined as flow through a tube whose length is smaller than its radius) is always somewhat turbulent.¹⁷ Clinically, airway-obstructing conditions such as epiglottitis or swallowed obstructions are often best viewed as breathing through an orifice (Fig. 4-6). Under such conditions, the approximate flow across the orifice varies inversely with the square root of the gas density:

Figure 4-6 Airway obstruction. Anterior-posterior and lateral radiographs of 18-month-old infant who had swallowed a marble. The presence of this esophageal foreign body caused acute airway obstruction from extrinsic compression of the trachea.

(From Badgwell JM, McLeod ME, Friedberg J: Airway obstruction in infants and children. Can J Anaesth 34:90, 1987.)

(16)

This is in contrast to laminar flow conditions, in which gas flow varies inversely with gas viscosity. The viscosity values for helium and oxygen are similar, but their densities are very different (Table 4-1). Table 4-2 provides useful data to allow comparison of gas flow rates through an orifice.¹⁸

TABLE 4-1 Viscosity and Density Differences of Anesthetic Gases

	Viscosity at 300 K	Density at 20° C
Air	18.6 µPa × s	1.293 g/L
Nitrogen	17.9 µPa × s	1.250 g/L
Nitrous oxide	15.0 µPa × s	1.965 g/L
Helium	20.0 µPa × s	0.178 g/L
Oxygen	20.8 µPa × s	1.429 g/L

Data from Haynes WM: CRC Handbook of chemistry and physics, ed 91, Boca Raton, FL, 2010, CRC Press, and Streeter VL, Wylie EB, Bedford KW: Fluid mechanics, ed 9, New York, 1998, McGraw-Hill.

TABLE 4-2 Gas Flow Rates Through an Orifice

1 Helium-Oxygen Mixtures

The low density of helium allows it to play a significant clinical role in the management of some forms of airway obstruction.¹⁹^–²² For instance, Rudow and colleagues described the use of helium-oxygen (heliox) mixtures in a patient with severe airway obstruction related to a large thyroid mass (see next section for clinical examples).¹⁸

The available percentage mixtures of helium and oxygen are typically 80 : 20 and 70 : 30. These mixtures are usually administered by a rebreathing face mask to patients who have an increased work of breathing due to airway pathology (e.g., edema) but for whom it is preferable to withhold endotracheal intubation at present.

Although the use of heliox mixtures in patients with upper airway obstruction has met with considerable success, the hope that this approach would also work well for patients with severe asthma has not been borne out. In a systematic review of seven clinical trials involving 392 patients with acute asthma, the authors cautioned that “existing evidence does not provide support for the administration of helium-oxygen mixtures to emergency department patients with moderate-to-severe acute asthma.”²³ A similar study noted that “heliox may offer mild-to-moderate benefits in patients with acute asthma within the first hour of use, but its advantages become less apparent beyond 1 hour, as most conventionally treated patients improve to similar levels, with or without it”; however, the authors suggested that its effect “may be more pronounced in more severe cases.” They concluded that “there are insufficient data on whether heliox can avert endotracheal intubation, or change intensive care and hospital admission rates and duration, or mortality.”²⁴

2 Clinical Vignettes

Rudow and colleagues reported the following clinical illustration of heliox therapy.¹⁸ A 78-year-old woman with both breast cancer and ophthalmic melanoma developed airway obstruction from a thyroid carcinoma that extended into her mediastinum and compressed her trachea. She had a 2-month history of worsening dyspnea, especially when positioned supine. On examination, inspiratory and expiratory stridor was present. The chest radiograph showed a large superior mediastinal mass and pulmonary metastases. A solid mass was identified on a thyroid ultrasound scan. Computed tomography revealed a large mass at the thoracic inlet and extending caudally. Clinically, the patient was exhausted and in respiratory distress.

A 78 : 22 heliox mixture was administered and provided almost instant relief, with improvements in measured tidal volume and oxygenation. Later, a thyroidectomy was carried out to alleviate the obstruction. For this procedure, topical anesthesia was applied to the airway and awake laryngoscopy and intubation were performed with the patient in the sitting position. After the airway was secured with the use of an armored tube, the patient was given a general anesthetic by intravenous induction. Extubation after the surgery was performed without complication.

Another interesting clinical scenario was published by Khanlou and Eiger.²⁵ They presented the case of a 69-year-old woman in whom bilateral vocal cord paralysis developed after radiation therapy. Heliox was successfully used for temporary management of the resultant upper airway obstruction until the patient was able to receive a tracheostomy.

A final clinical vignette was reported by Polaner,²⁶ who used the laryngeal mask airway and an 80 : 20 heliox mixture to administer anesthesia to a 3-year-old boy with asthma and a large anterior mediastinal mass. Clinical management involved an unusual combination of management strategies: the child was kept in the sitting position, spontaneous ventilation with a halothane-in-heliox inhalation induction was used, and airway stimulation was minimized by use of the laryngeal mask airway. However, the author cautioned that cases such as these can readily take a deadly turn, noting that “one must, of course, always be prepared to intervene with either manipulations of patient position in the event of airway compromise (including upright, lateral, and prone) or more aggressive strategies, such as rigid bronchoscopy and even median sternotomy (in the case of intractable cardiovascular collapse), or to allow the patient to awaken if critical airway or cardiovascular compromise becomes evident at any time during the course of the anesthesia.”²⁶

E Pressure Differences

From the analysis of equations governing laminar flow and turbulent flow, the pressure drop along the noncompliant portion of the airway is given approximately by the Rohrer equation ²⁷:

(17)

K₁ and K₂ are known as Rohrer constants. The physical interpretation of this equation is that airway pressure is governed by the sum of two terms:

1. Effects proportional to gas flow (laminar flow effects)

2. Effects proportional to the square of the gas flow (turbulent flow effects)

It can be seen that the lowest pressure loss across the airway (ΔP) would occur when is small (i.e., with predominantly laminar flow). However, it is known that under conditions of laminar flow, K₁ is largely influenced by viscosity rather than density, and K₂ (the turbulent term) is influenced primarily by density and not viscosity.

F Resistance to Gas Flow

When pressure readings are taken at each end of a horizontal tube with a fluid flowing through it, one notices that they are not identical: The pressure at the distal end of the tube is less than the pressure at the proximal end (with fluid flowing from the proximal to the distal end). This pressure loss is attributable to frictional losses incurred by the fluid when in contact with the inside of the tube. This is analogous to heat losses incurred by resistors in an electrical circuit (Fig. 4-7).

Figure 4-7 Analogy between laminar gas flow and flow of electricity through a resistor. A, Electrical flow rate (current) is measured in amperes; pressure difference (voltage) is measured in volts; resistance is measured in ohms and described by Ohm’s law. B, Gas flow rate is measured as volume/second (e.g., mL/s); pressure difference is measured as force/area (e.g., dynes/cm²); resistance is described by Poiseuille’s law. For gases, pressure difference = flow rate × resistance; for electricity, potential difference (voltage) = current × resistance.

(From Nunn JF: Nunn’s applied respiratory physiology, ed 4, Stoneham, MA, 1993, Butterworth-Heinemann.)

Frictional losses are irreversible; that is, the energy lost cannot be recovered by the fluid and is mostly lost as heat. If the tube is not horizontal, there are additional pressure differences attributable to height differences. The most common relation that describes the flow in a tube is the Bernoulli equation, which is valid for both laminar and turbulent flow ⁸:

(18)

where

V = velocity (m/s)

g = gravitational constant (9.81 m/s² or 9.81 N/kg)

P = pressure (pascals or N/m²)

ρ = density of fluid (kg/m³)

Z = height from an arbitrary point (datum) (m)

h_f = frictional losses (m)

Typical units are shown in square brackets. Equation 18 is in units of meters and is termed “meters of head loss.” This is typical of fluid mechanics equations. As mentioned previously, the Bernoulli equation is valid for both laminar and turbulent flow.

1 Endotracheal Tube Resistance

ETTs, like all tubes, offer resistance to fluid flow (Fig. 4-8). However, ETTs do not add external resistance to the normal airway; rather, they act as a substitute for the normal resistance of the airway from the mouth to the trachea, which accounts for 30% to 40% of normal airway resistance.²⁸ This is important because, although mechanical ventilators can overcome impedance to inspiratory flow during extended periods of artificial respiration, they do not augment passive exhalation. Resistance to exhalation through a long, small-diameter ETT, which is compounded by turbulence, can seriously constrain ventilation rate and tidal volume.^29,³⁰

Figure 4-8 Dependence of endotracheal tube (ETT) on flow. The data provided by Hicks in Table 4-3 can be used to show that ETT resistance increases nonlinearly with flow (because of turbulence effects). For pure laminar flow, resistance would be constant, regardless of flow.

The use of the ETT influences respiration in a number of ways. First, it decreases effective airway diameter and therefore increases the resistance to breathing. Resistance is further increased by the curved nature of the tube; resistance measurements are typically about 3% higher than if the tubes were straight.³¹ Also, the passage from the mouth to the larynx is not a smooth curve and may create additional turbulence. Second, studies show that intubated patients experience decreased peak flow rates (inspiratory and expiratory), decreased forced vital capacity, and decreased forced expiratory volume in 1 second (FEV₁).³² However, the tube may paradoxically increase peak flow rates during forced expiration by preventing dynamic compression of the trachea.³² Finally, the tube may cause mechanical irritation of the larynx and trachea that may lead to a reflex constriction of the airway distal to the tube.³³

The combination of tube and connector may cause higher resistance than the tube alone. Moreover, because of turbulence at component connections, the total resistance of a system is not necessarily the sum of the resistances of its component parts, especially if sharp-angled connectors are used (see Fig. 4-5).^25,³⁴ In addition, humidified gases contribute to slightly higher resistances because of the increased density of moist gas, and the resistance of single-lumen tubes is generally lower than that of double-lumen tubes.³⁵

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